Question 9
A ladder 10 m long reaches a window 8 m above the ground. Find the distance of the foot of the ladder from the base of the wall.

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Solution

Let BA be the wall and AC be the ladder,
Therefore, by applying Pythagoras theorem
$A C^{2} = A B^{2} + B C^{2}$
$10^{2} = 8^{2} + B C^{2}$
$B C^{2} = 100 - 64$
$B C^{2} = 36$
BC = 6m
Therefore, the distance of the foot of the ladder from the base of the wall is 6 m.

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Pythagoras Theorem

Standard VII Mathematics

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Question 9 A ladder 10 m long reaches a window 8 m above the ground. Find the distance of the foot of the ladder from the base of the wall.

Let BA be the wall and AC be the ladder, Therefore, by applying Pythagoras theorem AC2=AB2+BC2 102=82+BC2 BC2=100−64 BC2=36 BC = 6m Therefore, the distance of the foot of the ladder from the base of the wall is 6 m.

Question 9
A ladder 10 m long reaches a window 8 m above the ground. Find the distance of the foot of the ladder from the base of the wall.

Let BA be the wall and AC be the ladder,
Therefore, by applying Pythagoras theorem
$A C^{2} = A B^{2} + B C^{2}$
$10^{2} = 8^{2} + B C^{2}$
$B C^{2} = 100 - 64$
$B C^{2} = 36$
BC = 6m
Therefore, the distance of the foot of the ladder from the base of the wall is 6 m.