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Question

A ladder 10 m long reaches a window 8 m above the ground. Find the distance between the foot of the ladder and the base of the wall.


A

8m

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B

6.5m

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C

7m

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D

6m

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Solution

The correct option is D

6m



Let BA be the wall and AC be the ladder.
Therefore, by Pythagoras theorem, we have,
AC2=AB2+BC2
102=82+BC2
BC2=10064
BC2=36
BC=6 m
Therefore, the distance between the foot of the ladder and the base of the wall is 6 m.


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