A ladder 10 m long reaches a window 8 m above the ground. Find the distance between the foot of the ladder and the base of the wall.
6m
Let BA be the wall and AC be the ladder.
Therefore, by Pythagoras theorem, we have,
AC2=AB2+BC2
102=82+BC2
BC2=100−64
BC2=36
BC=6 m
Therefore, the distance between the foot of the ladder and the base of the wall is 6 m.