A ladder 10 m long reaches a window above the ground. The distance of the foot of the ladder from the base of the wall is 6 m. Then the height of the ladder from the ground is
8m
Let BA be the wall and AC be the ladder.
Therefore, by Pythagoras theorem, we have,
AC2=AB2+BC2
102=AB2+62
AB2=100−36
AB2=64
AB=8 m
Therefore, the height of the ladder from the ground is 8 m.