A lady covers a certain distance on her scooty. Had she moved 9 kmph faster she would have taken 2 hrs less. If she had moved 6 kmph slower, she would have taken 2 hrs more. Find the distance.
360 km
Let distance = `x' m
Usual rate = `y' kmph
xy−xy+9=2 hr
2y(y+9) = 9x ---- (1)
xy−6−xy=2hr
y(y-6) = 3x -- (2)
Divide equations (1) and (2) - by solving we get x = 360 km