Question

A lift is accelerating upwards with 25 $\frac{m}{s^2}$. In lift's reference frame, a man of 50 kg will feel a pseudo force of in direction .

• A. 1250 N
• B. 750 N
• C. upward
• D. downward

Answer 1

Answer: (A), (D)

The correct options are
A 1250 N
D downward

The pseudo force in a non-inertial frame is given by, ${\left|\overrightarrow{F}\right|}_{pseudo}=Ma$
where, M = mass of an object in that frame
a = acceleration of the frame
Thus, F = 50 $\times$ 25 N
= 1250 N
The direction will be opposite to the acceleration of the frame. In this case it is vertically downwards.
Therefore, ${\overrightarrow{F}}_{pseudo}=1250N,$ downwards.