A light aircraft has a wing area of 15m2 and flies at 60m/s in level flight. If the air velocity over the upper surface of the wing is 15% greater, then the magnitude of the lift developed (in N) is (nearly)
(given: density of air is 1.2kg/m3)
A
5255
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B
7500
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C
2525
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D
10450
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Solution
The correct option is D10450 Velocity of air in upper wing=115100×60=69m/s So, Pressure difference across the wings 12×1.2×(692−602)Pa =696.6Pa So, Magnitude of life developed = pressure diff × Area =(696.6×15)N≈10449N