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Question

A (Light pink colour complex) Pb3O4/dil.HNO3−−−−−−−−−ΔHMnO4H2S/H+−−−−A (Light pink colour complex).
Calculate CFSE value in light pink colour complex.

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Solution

Pink coloured complex: [Mn(H2O)6]2+
Mn2+(3d5) in [Mn(H2O)6]++,Δo<P
CFSE of the pink coloured complex:
=3×(25Δc)+2×[35Δo]=0
204408_147566_ans.png

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