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Byju's Answer
Standard XII
Chemistry
Hess' Law
A Light pink ...
Question
A (Light pink colour complex)
P
b
3
O
4
/
d
i
l
.
H
N
O
3
−
−−−−−−−−−
→
Δ
H
M
n
O
4
H
2
S
/
H
+
−
−−−−
→
A
(Light pink colour complex).
Calculate
C
F
S
E
value in light pink colour complex.
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Solution
⇒
Pink coloured complex:
[
M
n
(
H
2
O
)
6
]
2
+
M
n
2
+
(
3
d
5
)
in
[
M
n
(
H
2
O
)
6
]
+
+
,
Δ
o
<
P
CFSE of the pink coloured complex:
=
3
×
(
−
2
5
Δ
c
)
+
2
×
[
3
5
Δ
o
]
=
0
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