A light ray falls on one of the faces of a prism at an angle 40 so that it suffers minimum deviation of 30 degrees. Find the angle of prism and angle of refraction at the given surface.

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Solution

For the minimum angle of deviation, the ane of incidence must be equal to the angle of emergence.

As we know,

∆= (I+i) –A

∆= Angle of deviation

I= Angle of incidence

i= Angle of emergence

A= Angle of the prism

30=(240) –A

A=50degree

∆= (I+i) – (r+r')

r=r' = angle of refraction

30=(240) –2*r

r=25 degree

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