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Standard XII

Physics

Pulley

A light strin...

Question

A light string passing over a smooth light pulley connects two blocks of masses $m_{1}$ and $m_{2}$ (vertically). If the acceleration of the system is g/8, then the ratio of the masses is

8 : 1

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9 : 7

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4 : 3

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5 : 3

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Solution

The correct option is B 9 : 7
$a = \frac{m_{2} - m_{1}}{m_{2} + m_{1}} . g$
$∴ \frac{g}{8} = \frac{m_{2} - m_{1}}{m_{2} + m_{1}} . g ∴ \frac{m_{2} - m_{1}}{m_{2} + m_{1}} = \frac{1}{8} \Rightarrow \frac{m_{2}}{m_{1}} = \frac{9}{7}$

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A light string passing over a smooth light pulley connects two blocks of masses m1 and m2 (vertically). If the acceleration of the system is g/8, then the ratio of the masses is

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A light string passing over a smooth light pulley connects two blocks of masses $m_{1}$ and $m_{2}$ (vertically). If the acceleration of the system is g/8, then the ratio of the masses is

The correct option is B 9 : 7
$a = \frac{m_{2} - m_{1}}{m_{2} + m_{1}} . g$
$∴ \frac{g}{8} = \frac{m_{2} - m_{1}}{m_{2} + m_{1}} . g ∴ \frac{m_{2} - m_{1}}{m_{2} + m_{1}} = \frac{1}{8} \Rightarrow \frac{m_{2}}{m_{1}} = \frac{9}{7}$