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Pulley

A light strin...

Question

A light string passing over a smooth light pulley connects two blocks of masses $m_{1}$ and $m_{2}$ (vertically). If the acceleration of the system is g/8 then the ratio of the masses is

A

8 : 1

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B

9 : 7

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C

4 : 3

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D

5 : 3

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Solution

The correct option is B
9 : 7

$a = (\frac{m_{2} - m_{1}}{m_{1} - m_{2}}) g = \frac{g}{g}$ ; by solving $\frac{m_{2}}{m_{1}} = \frac{9}{7}$

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