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Standard XII

Physics

Pulley

A light strin...

Question

A light string passing over a smooth light pulley connects two blocks of masses $m_{1}$ and $m_{2}$ (vertically). If the acceleration of the system is g/8 then the ratio of the masses is

8 : 1

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9 : 7

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4 : 3

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5 : 3

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Solution

The correct option is B
9 : 7

$a = (\frac{m_{2} - m_{1}}{m_{1} - m_{2}}) g = \frac{g}{g}$ ; by solving $\frac{m_{2}}{m_{1}} = \frac{9}{7}$

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A light string passing over a smooth light pulley connects two blocks of masses m1 and m2 (vertically). If the acceleration of the system is g/8 then the ratio of the masses is

The correct option is B 9 : 7 a=(m2−m1m1−m2)g=gg; by solving m2m1=97

A light string passing over a smooth light pulley connects two blocks of masses $m_{1}$ and $m_{2}$ (vertically). If the acceleration of the system is g/8 then the ratio of the masses is

The correct option is B
9 : 7

$a = (\frac{m_{2} - m_{1}}{m_{1} - m_{2}}) g = \frac{g}{g}$ ; by solving $\frac{m_{2}}{m_{1}} = \frac{9}{7}$