A line APB of constant length meets the x-axis at A and y-axis at B. If AP=b,PB=a and the line slides with its extremities on the coordinate axes, show that equation of the locus of the point P is x2a2+y2b2=1
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Solution
If P be the point (h,k) on the line, then h=OQ=RP=acosθ, k=PQ=bsinθ Eliminating θ, we get x2a2+y2b2=1