1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A line L1:2x−2y+5=0 is rotated about its point of intersection with y−axis such that L1 becomes L2 and area of the triangle formed by L1,L2 and x=4 is 13 sq. unit, then L2 will be

A
21x8y+20=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
5x+8y=20
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
5x+8y+20=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
21x8y=20
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct options are A 21x−8y+20=0 B 5x+8y=20y− intercept of the L1 2×0−2y+5=0 y=52 So, A=(0,52) Intersection point of the L1 with the line x=4 2×4−2y+5=0y=132 So, B=(4,132) Let the point C on the line L2 and x=4 be, C=(4,k) So the area of the triangle will be, A=12∣∣ ∣ ∣ ∣ ∣∣∣∣ ∣ ∣ ∣ ∣∣10521413214k∣∣ ∣ ∣ ∣ ∣∣∣∣ ∣ ∣ ∣ ∣∣ k=0,13 For k=0 the line will be, x4+2y5=1⇒5x+8y=20 For k=13 the line will be, y−13x−4=13−524⇒21x−8y+20=0

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Rectangular Hyperbola
MATHEMATICS
Watch in App
Explore more
Join BYJU'S Learning Program