Question

A line passes through P(1, 2) such that its intercept between the axes is bisected at P. Find the equation of line.

Answer 1

We know that, equation of the intercept is

$\frac{x}{a}+\frac{y}{b}=1$

It is given that,

$1=\frac{a+0}{2}$ and $2=\frac{0+b}{2}$

$\Rightarrow$ a = 2 and b = 4

Hence, the equation of line is $\frac{x}{2}+\frac{y}{4}=1$

i.e. 2x + y - 4 = 0.