A line passing through $(3, - 2)$ and is parallel to the line $5 x + 6 y + 9 = 0$ . The value of $x$ intercept made by the line is

3

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\frac{6}{5}

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\frac{3}{5}

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\frac{1}{2}

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Solution

The correct option is C $\frac{3}{5}$
$5 x + 6 y + 9 = 0$
A line parallel to the given line
$5 x + 6 y + c = 0$
Putting the point $(3, - 2)$
$15 - 12 + c = 0 \Rightarrow c = - 3$
The required equation of the line is,
$5 x + 6 y - 3 = 0$
$x$ intercept of the line
$5 x = 3 \Rightarrow x = \frac{3}{5}$

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