A line passing through the point of intersection of $2 x + y = 5$ and $x + 3 y + 8 = 0$ and parallel to the line $3 x + 4 y = 7$

3 x + 4 y + 3 = 0

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3 x + 4 y = 0

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4 x - 3 y + 3 = 0

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4 x - 3 y = 0

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Solution

The correct option is A $3 x + 4 y + 3 = 0$
Let us find out point os intersetion of $2 x + y = 5$
$2 + 3 y + 8 = 0$
$- 6 y - 16 + y = 5$
$- 5 y = 21$
$y=−215x=dfrac235$
Now equation of fire with slope $\frac{- 3}{4}$ passing through
$(\frac{23}{5}, \frac{21}{5})$ is
$y + \frac{21}{5} = \frac{- 3}{4} (x - \frac{23}{5})$
$4 y + \frac{84}{5} = - 3 x + \frac{69}{5}$
$3 x + 4 y + 3 = 0$
$A$ is correct.

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Similar questions

x - y - 1 = 0

2 x - 3 y + 1 = 0

3 x + 4 y - 14 = 0

Equations to the sides of a triangle are $x - 3 y = 0$ , $4 x + 3 y = 5$ and $3 x + y = 0$ . The line $3 x - 4 y = 0$ passes through the

x - 3 y = 0, 4 x + 3 y = 5

3 x + y = 0

3 x - 4 y = 0

3 x - 4 y + 1 = 0, 3 x - 4 y + 3 = 0, 4 x - 3 y - 1 = 0

4 x - 3 y - 2 = 0,

2 x + y = 5

x + 3 y + 8 = 0

3 x + 4 y = 7

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