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Question

A liquid of mass m and specific heat c is at a temperature 2T. Another liquid of mass m/2 and specific heat 2c is at a temperature T. If these two liquids are mixed, the resulting temperature of the mixture is:


A

(23)T

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B

(85)T

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C

(35)T

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D

(32)T

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Solution

The correct option is D

(32)T


Given:
Mass of liquid 1, m1=m,
Specific heat of liquid 1, c1=c,
Initial temperature of liquid 1, T1=2T
Mass of liquid 2, m2=m2
Specific heat of liquid 2, c2=2c,
Initial temperature of liquid 2, T2=T

Let the temperature of mixture be Tm.

Heat lost by liquid 1 = Heat gained by liquid 2.
m1c1(T1Tm)=m2c2(TmT2)
mc(2TTm)=m2×2c×(TmT)
Tm=32T


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