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Question

A liquid rises to a height of 5 cm in a glass capillary of radius 0.02 cm. What will be the height of the same liquid in a glass capillary of radius 0.04 cm?

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Solution

Given: h1=5 cm
r1=0.02 cm
r2=0.04 cm
h2=?
T=rhρg2cosθ
r1h1=r2h2
5×0.02=0.04×h2
h2=5×0.020.04=2.5 cm

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