A list of species having the formula $X Z_{4}$ is given below: $X e F_{4}, S F_{4}, S i F_{4}, B F_{4}^{-}, B r F_{4}^{-}, [C u (N H_{3})_{4}]^{2 +}, [F e C l_{4}]^{2 -}, [C o C l_{4}]^{2 -} and [P t C l_{4}]^{2 -} .$ Defining shape on the basis of the location of X and Z atoms, the total number of species having a square planar shape is

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Solution

$X e F_{4}, B r F_{4}^{-}, [C u (N H_{3})_{4}]^{2 +}, [P t C l_{4}]^{2 -}$ are square planar
$S F_{4}$ is sea saw
$S i F_{4}, B F_{4}^{-}, [F e C l_{4}]^{2 -}, [C o C l_{4}]^{2 -}$ are tetrahedral

Compound/Ion Magnetic nature of compound

1. $[N i (C O)_{4}]$ Diamagnetic

2. $[N i C l_{4}]^{2 -}$ Paramagnetic

3. $[C o (N H_{3})_{4} C l_{2}] C l$ Diamagnetic

4. $N a_{3} [C o F_{6}]$ Paramagnetic

5. $N a_{2} O_{2}$ Diamagnetic

6. $C s O_{2}$ Paramagnetic

So total number of paramagnetic compound is 3.

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Similar questions

_{4}

X e F_{4}, S F_{4}, S i F_{4}, B F_{4}^{-}, B r F_{4}^{-}, [C u (N H_{3})_{4}]^{2 +}, [F e C l_{4}]^{2 -}, [C o C l_{4}]^{2 -}

[P t C l_{4}]^{2 -}

X Z_{4}

X e F_{4}, S F_{4}, S i F_{4}, B F_{4}^{⊖}, [C u (N H_{3})_{4}]^{2 +}, [F e C l_{4}]^{2 -}, [C o C l_{4}]^{2 -} a n d [P t C l_{4}]^{2 -} .

X Z_{4}

S i F_{4}, S F_{4}, X e F_{4}, B r F_{4}^{-}, B F_{4}^{-}, [C u (N H_{3})_{4}]^{2 +}, [F e C l_{4}]^{-}, [N i (C O)_{4}]

[P t C l_{4}]^{2 -}

X Z_{4}

X e F_{4}, S F_{4}, S i F_{4}, B F_{4}^{-} a n d B r F_{4}^{-}

X

Z

S F_{4}, B F_{4}^{-}, C l F_{3}, A s F_{3}, P C l_{5}, B r F_{5}, X e F_{4}, S F_{6}

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