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Question

A long solenoid has 1000turns. When a current of 4A flows through it, the magnetic flux linked with each turn of the solenoid is 4×10-3Wb. What is the self-inductance of the solenoid?


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Solution

Step 1: GIven data

A long solenoid has (N)=1000turns

Current I=4A

Magnetic flux ϕ=4×10-3Wb

Step 2: Formula used

ϕ=LI

This formula belongs to the self-inductance of the solenoid.

Here, ϕ=magnetic flux

L= self-inductance

I=current

Step 3: Calculating self-inductance

So, we have flux linked with each turn

ϕ=4×10-3Wb

Total flux linked =1000×4×10-3

Now, on the basis of the formula

ϕ=LIL=ϕI

Now on putting the values

L=4×10-34

So, L=1H

Hence, the self-inductance of the solenoid is L=1H.


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