Question

Two solenoids are wound around the same pipe so that the magnetic field of one passes through the turns of the other. Solenoid $1$ has $700$ turns and solenoid $2$ has $400$ turns. When the current in solenoid $1$ is $6.52A$, the average flux through each turn of solenoid $2$ is $0.0320Wb$. What is the mutual inductance of the pair of solenoids?

Answer 1

$M=\frac{N_2{\varphi }_2}{i_1}=\frac{\left(400\right)\left(0.032\right)}{6.52}$
$=1.96H$