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Question
A long solenoid has 500 turns. When a current of 2 A is passed through it, the resulting magnetic flux linked with each turn of the solenoid is 4×10−3 Wb. The self-inductance of the solenoid is
A long solenoid has 500 turns. When a current of 2 A is passed through it, the resulting magnetic flux linked with each turn of the solenoid is 4×10−3 Wb. The self-inductance of the solenoid is
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Solution
The correct option is A 1.0 H
Given flux per turn =4×10−3i = 2 A
No of turns = 500
Total flux = 500×4×10−3 = 2 A
Flux, ϕ = Li2 = L×2L = 1 H
Given flux per turn =4×10−3i = 2 A
No of turns = 500
Total flux = 500×4×10−3 = 2 A
Flux, ϕ = Li2 = L×2L = 1 H