Question

A long solenoid has $500turns$. When a current of $2A$ is passed through it, the resulting magnetic flux linked with each turn of the solenoid is $4\times {10}^{-3}Wb$. The self-inductance of the solenoid is:

• A. $4.0H$
• B. $2.5H$
• C. $2.0H$
• D. $1.0H$

Answer 1

The correct option is D $1.0H$

Given:-

$\Phi =4\times {10}^{-3}Wb/turn$

$N=$ Number of turns $=500$

$I=$ Current flowing $=2A$

$L=$ Self-inductance $=?$

Formula:-

$N\times \Phi =L\times I$

$\therefore 500\times 4\times {10}^{-3}=L\times 2$

$\therefore L=\frac{500\times 4\times {10}^{-3}}{2}$

$\therefore L=1H$

$\therefore$ Self-inductance of solenoid is $1.0H$