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Question

A long straight wire carries a certain current and produces a magnetic field 2×104Wbm2 at perpendicular distance of 5 cm from the wire. An electron situated at 5 cm from the wire. An electron situated at 5 cm from the wire moves with a velocity 107m/s towards the wire along perpendicular to it. The force experienced by the electron will be (charge on electron 1.6×101C

A
3.2 N
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B
3.2×1016N
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C
1.6×1016N
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D
zero
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Solution

The correct option is B 3.2×1016N
Given magnetic field ^B=2×104Wbm2
velocity of electronv=107m/s
charge of electron q=1.6×1019C
We know magnetic forceF=qvBsinθ
F=1.6×1019×107×2×104=3.2×1016
Here θ=90 as mentioned electrons moving in a perpendicular direction to the wire viz. sin90=1

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