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Question

A long straight wire carries a certain current and produces a magnetic field 2 ×104 Wb m2 at a perpendicular distance of 5 cm from the wire. A particle say 'c' having charge equal to that of an electron is situated at 5 cm from the wire moves with a velocity of 107 m/s towards the wire perpendicularly. The magnitude of force experienced by the particle will be (charge of an electron =1.6×1019 C )

A
3.2 N
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B
3.2×1016 N
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C
1.6×1016 N
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D
0 N
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Solution

The correct option is B 3.2×1016 N
The situation is as shown in the figure.


Here, v=107 m/s,
B=2×104 Wb/m2
The magnitude of the force experienced by the electron is
F=evBsin(θ)
( v and B are perpendicular to each other)
=evBsin(900)=1.6×1019×107×2×104×1=3.2×1016 N
Here, negative sign denotes the direction of force.

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