Question

# A longitudinal wave is produced on a toy slinky. The wave travels at a speed of 30 cm/s and the frequency of the wave is 20 Hz. What is the minimum separation between the consecutive compressions of the slinky?

A
0.015m
B
0.03m
C
0.045m
D
0.06m

Solution

## The correct option is C $$0.015m$$The relationship between the frequency, wavelength and speed of sound or velocity is given as follows.$$Wavelength\quad \lambda =\dfrac { wave\quad velocity\quad v }{ Frequency\quad \nu }$$In the question, the velocity of sound is 30 cm/s, that is 0.3 m/s and frequency=20 Hz is given.The distance between two consecutive compression is equal to the wavelength of the wave, therefore,$$Wavelength\quad \lambda =\dfrac { v }{ \nu } =\dfrac { 0.3\quad m/s }{ 20\quad Hz } =0.015\quad m$$.Hence, the wavelength of the sound wave is given as 0.015 m.Physics

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