A longitudinal wave travels through a coiled spring at a speed of $4 m s^{- 1}$ . The distance between two consecutive compression is $20 c m$ . Find the frequency of the wave.

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Solution

We know that,

Wavelength = distance between two consecutive compressions $(h e r e w a v e l e n g t h = 20 c m = 0.2 m)$

Also, $s p e e d = f r e q u e n c y \times w a v e l e n g t h$

or, $F r e q u e n c y = \frac{s p e e d}{w a v e l e n g t h}$

= $\frac{4}{0.2}$ = $20 h e r t z$

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A longitudinal wave travels through a coiled spring at a speed of $4 m s^{- 1}$ . The distance between two consecutive compression is $20 c m$ . Find the frequency of the wave?

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A longitudinal wave travels through a coiled spring at a speed of 4 ms−1. The distance between two consecutive compression is 20 cm. Find the frequency of the wave.

We know that, Wavelength = distance between two consecutive compressions (here wavelength = 20 cm = 0.2 m) Also, speed = frequency×wavelength or, Frequency = speedwavelength = 40.2 = 20 hertz

A longitudinal wave travels through a coiled spring at a speed of $4 m s^{- 1}$ . The distance between two consecutive compression is $20 c m$ . Find the frequency of the wave.

We know that,

Wavelength = distance between two consecutive compressions $(h e r e w a v e l e n g t h = 20 c m = 0.2 m)$

Also, $s p e e d = f r e q u e n c y \times w a v e l e n g t h$

or, $F r e q u e n c y = \frac{s p e e d}{w a v e l e n g t h}$

= $\frac{4}{0.2}$ = $20 h e r t z$