A loop of area 0.5m2 is placed in a magnetic field of strength 2T in direction making an angle of 30o with the field. The magnetic flux linked with the loop will be
A
12Wb
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B
√32Wb
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C
2Wb
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D
√32Wb
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Solution
The correct option is D√32Wb Magnetic flux linked with an area is given by ϕB=∫−→B.−→dS Here field is uniform therefore, ϕB=BScosθ ϕB=2×0.5×√3/2 ϕB=√3/2.