A lump of copper of mass 890 g is dipped into a glass filled to the brim with water. What volume of water will overflow? (The density of copper = 8.9 g/cm³.)

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Solution

Mass of the lump of copper = 890 g
Density of copper = 8.9 g/cm³
So, the volume of the lump of copper = Mass / Density
= 890 g / 8.9 g/cm³
= 100 cm³
Thus, when the lump of copper is dipped into a glass filled to the brim with water, the volume of water that will overflow is 100 cm³.

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A lump of copper of mass 890 g is dipped into a glass filled to the brim with water. What volume of water will overflow? (The density of copper = 8.9 g/cm3.)

Mass of the lump of copper = 890 gDensity of copper = 8.9 g/cm3So, the volume of the lump of copper = Mass / Density = 890 g / 8.9 g/cm3 = 100 cm3Thus, when the lump of copper is dipped into a glass filled to the brim with water, the volume of water that will overflow is 100 cm3.

A lump of copper of mass 890 g is dipped into a glass filled to the brim with water. What volume of water will overflow? (The density of copper = 8.9 g/cm³.)

Mass of the lump of copper = 890 g
Density of copper = 8.9 g/cm³
So, the volume of the lump of copper = Mass / Density
= 890 g / 8.9 g/cm³
= 100 cm³
Thus, when the lump of copper is dipped into a glass filled to the brim with water, the volume of water that will overflow is 100 cm³.