A lump of copper of mass 890 g is dipped into a glass filled to the brim with water. What volume of water will overflow? (The density of copper = 8.9 g/cm³.)

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Solution

Mass of the lump of copper = 890 g

Density of copper = 8.9 g/cm³

So, the volume of the lump of copper = Mass / Density

= 890 g / 8.9 g/cm³

= 100 cm³

Thus, when the lump of copper is dipped into a glass filled to the brim with water, the volume of water that will overflow is 100 cm³.

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A lump of copper of mass 890 g is dipped into a glass filled to the brim with water. What volume of water will overflow? (The density of copper = 8.9 g/cm3.)

Mass of the lump of copper = 890 g Density of copper = 8.9 g/cm3 So, the volume of the lump of copper = Mass / Density = 890 g / 8.9 g/cm3 = 100 cm3 Thus, when the lump of copper is dipped into a glass filled to the brim with water, the volume of water that will overflow is 100 cm3.

A lump of copper of mass 890 g is dipped into a glass filled to the brim with water. What volume of water will overflow? (The density of copper = 8.9 g/cm³.)

Mass of the lump of copper = 890 g

Density of copper = 8.9 g/cm³

So, the volume of the lump of copper = Mass / Density

= 890 g / 8.9 g/cm³

= 100 cm³

Thus, when the lump of copper is dipped into a glass filled to the brim with water, the volume of water that will overflow is 100 cm³.