A machine that has a mechanical Advantage of 9 is used for a load of 765 Kgf. Find the required effort.

50 kgf

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90 kgf

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85kgf

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20 kgf

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Solution

The correct option is C
85kgf

Given, Mechanical Advantage = 9

Load = 765 kgf

$M e c h a n i c a l A d v a n t a g e = \frac{L o a d}{E f f o r t}$

$E f f o r t = \frac{L o a d}{A d v a n t a g e}$

$= \frac{765 k g f}{9} = 85 k g f$

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