A magnet of magnetic moment $M$ and length $2 l$ is bent at its mid-point such that the angle of bending is $60^{o}$ The new magnetic moment is

M

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\frac{M}{2}

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2 M

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\frac{M}{\sqrt{2}}

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Solution

The correct option is B $\frac{M}{2}$
Magnetic moment is a vector quantity.
$M = \sqrt{M_{1}^{2} + M_{2}^{2} + M_{1} M_{2} cos θ}$
$M = \sqrt{M^{2} / 4 + M^{2} / 4 + 2 M^{2} / 4 cos 120^{0}}$ (angle between the vectors would be $120^{o}$ )
$M = M / 2$

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The correct option is B $\frac{M}{2}$
Magnetic moment is a vector quantity.
$M = \sqrt{M_{1}^{2} + M_{2}^{2} + M_{1} M_{2} cos θ}$
$M = \sqrt{M^{2} / 4 + M^{2} / 4 + 2 M^{2} / 4 cos 120^{0}}$ (angle between the vectors would be $120^{o}$ )
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