Question

A magnetic flux of 8 × 10⁻⁴ weber is linked with each turn of a 200-turn coil when there is an electric current of 4 A in it. Calculate the self-inductance of the coil.

Answer 1

Given:
Magnetic flux linked with each turn, ϕ = 8 × 10⁻⁴ Wb
Number of turns, n = 200
Current, i = 4 A
Self-inductance is calculated as:
$L=\left(\frac{n\varphi }{i}\right)$
= $\left(\frac{200}{4}\right)\times \left(8\right)\times \left({10}^{-4}\right)$
= 4 × 10⁻² H