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Question

A man 'a' goes from his home to somewhere with the speed of 40km/hr. After 15 min, second man 'b' also starts his journey from 'a' house with the speed of 45km/hr and he decided to overtake 'a'. At what distance from 'a' house he travels to overtake 'a' and what time he takes to overtake him

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Solution

Initial distance between the two men = 40km/hr×0.25hr=10km
Relative velocity of two men = 45km/hr40km/hr=5km/hr
Therefore, time taken to cover the distance = 10km5km/hr=2hr
Therefore, b overtakes a 2 hours after b started. Also, the distance from the house is:
45km/hr×2hr=90km

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