A man buys two cycles for a total cost of Rs. 900. By selling one cycle at a loss of 20% and the other at a profit of 25%, he makes a profit of Rs. 90 on the whole transaction. Find the cost price of a cycle which is costlier than the other.

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Solution

Let the cost of one cycle is x
The cost of another cycle=(900-x)
Then according to the question
$\Rightarrow (900 - x) \times \frac{25}{100} - x \times \frac{20}{100} = 90$
$\Rightarrow \frac{900 - x}{4} - \frac{x}{5} = 90$
$\Rightarrow \frac{4500 - 5 x - 4 x}{20} = 90$
$\Rightarrow 4500 - 9 x = 1800$
$\Rightarrow - 9 x = - 2700 \Rightarrow x = 300$
Hence CP of one cycle = $300 R s .$
And cost of another cycle $= 900 - 300 = 600 R s .$

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A man buys two cycles for a total cost of Rs. 900. By selling one cycle at a loss of 20% and the other at a profit of 25%, he makes a profit of Rs. 90 on the whole transaction. Find the cost price of a cycle which is costlier than the other.

Let the cost of one cycle is xThe cost of another cycle=(900-x)Then according to the question⇒(900−x)×25100−x×20100=90⇒900−x4−x5=90⇒4500−5x−4x20=90⇒4500−9x=1800⇒−9x=−2700⇒x=300Hence CP of one cycle =300Rs.And cost of another cycle =900−300=600Rs.