A man covers a certain distance between his house and office on a Scooter.Having an average speed of 30 km/hr, he reaches office late by 10 minutes.However,with a speed of 40 km/hr, he reaches his office 5 minutes earlier.the distance between his house and office is

30

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10

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20

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Solution

The correct option is A $30$ km
When speed is 30 km/hr he reaches 10 minutes late when Speed is 40 km/hr he reaches 5 minutes earlier.
Let Distance be D and T=D/S
$\frac{D}{30} - \frac{D}{40} = 15 m i n o r \frac{15}{60} h r$

$\frac{4 D - 3 D}{120} = \frac{15}{60}$
$D = 30$ km

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A man covers a certain distance between his house and office on a Scooter.Having an average speed of 30 km/hr, he reaches office late by 10 minutes.However,with a speed of 40 km/hr, he reaches his office 5 minutes earlier.the distance between his house and office is

The correct option is A 30 kmWhen speed is 30 km/hr he reaches 10 minutes late when Speed is 40 km/hr he reaches 5 minutes earlier.Let Distance be D and T=D/SD30−D40=15minor1560hr4D−3D120=1560D=30 km

The correct option is A $30$ km
When speed is 30 km/hr he reaches 10 minutes late when Speed is 40 km/hr he reaches 5 minutes earlier.
Let Distance be D and T=D/S
$\frac{D}{30} - \frac{D}{40} = 15 m i n o r \frac{15}{60} h r$

$\frac{4 D - 3 D}{120} = \frac{15}{60}$
$D = 30$ km