A man drops a ball downside from the roof of a tower of height 400 meters. At the same time another ball is thrown upside with a velocity 50metersec. from the surface of the tower, then they will meet at which height from the surface of the tower
A
100 meters
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B
320 meters
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C
80 meters
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D
200 meters
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Solution
The correct option is A 100 meters Let both balls meet at point P after time t. The distance travelled by ball A, h1=12gt2 The distance travelled by ball B, h2=ut−12gt2 h1+h2=400m⇒ut=400,t=40050=8sec ∴h1=320m and h2=80m