Question

A man goes $1\cdot 2km$ due to North and then $0\cdot 5km$ due West. Find the least distance between his initial and final positions.

Answer 1

Least distance between the INitial and final position can be found by Pythagoras theorem.
Thus, $(D{)}^2=(DistanceNorth{)}^2+(DistanceWest{)}^2$
$D^2=(1.2{)}^2+(0.5{)}^2$
$D^2=1.69$
$D=1.3km$
Least distance between initial and final position is $1.3km$