Question

A man goes to a garden and runs in the following manner: From the starting point, he goes west $25m$ then due north $60m$, then due east $80m$ and finally due south $12m.$ The distance between the finishing point and the starting point is:

• A. $177m$
• B. $103m$
• C. $83m$
• D. $73m$

Answer 1

The correct option is D $73m$

Let $A$ be the starting point and $B$ be the finishing point.

As can be seen from the figure, we have to find $AB$.

$BC=80m-25m=55m$,

$AC=60m-12m=48m$

By Pythagoras' Theorem,

$A{B}^2=A{C}^2+B{C}^2={48}^2+{55}^2$

$=2304+3025=5329$

$\Rightarrow AB=\sqrt{5329}=73m$.