Question

A man had $32,48,64$ beads in $3$ different bags. The least number of beads were blue in each bag. Each bag had the same number of blue beads. How many blue colour beads were in each bag?

• A. $20$
• B. $10$
• C. $16$
• D. $24$

Answer 1

The correct option is C $16$

$32=2\times 2\times 2\times 2\times 2$
$48=2\times 2\times 2\times 2\times 3$
$64=2\times 2\times 2\times 2\times 2\times 2$
HCF is $16.$
So, there are $16$ blue beads in each bag
Therefore, $B$ is the correct answer.