Question

A man has only $20$ paise coins and $25$ paise coins in his purse. If he has $50$ coins in all totaling Rs. $11.25$, how many coins of each kind does he have?

• A. $25$ coins of each kind
• B. $16$ coins of each kind
• C. $44$ coins of each kind
• D. $32$ coins of each kind

Answer 1

The correct option is A $25$ coins of each kind

Let no of $20$p coins $=x$
No of $25$p coins $=y$
According to the question
$x+y=50$
$\Rightarrow x=50-y.....eq1$
And $20x+25y=1125\Rightarrow 4x+5y=\mathrm{225....}eq2$
Put the value of $x$ from $eq1$
$\Rightarrow 4(50-y)+5y=\mathrm{225......}eq3$
$\Rightarrow 200-4y+5y=225\Rightarrow y=25$
Put $y=25$ in $eq1$
$\Rightarrow x+25=50\Rightarrow x=25$

No of $20$p coins $=25$

No of $25$p coins $=25$