Question

Sumitra has $Rs.34$ in $50-$paise and $25-$paise coins. If the number of $25-$paise coins is twice the number of $50-$paise coins, how many coins of each kind does she have.

Answer 1

Let Sumitra has ${}^{\prime }{x}^{\prime }$ 50-paise coins and ${}^{\prime }{y}^{\prime }$ 25-paise coins

She has $Rs34$

Since $Rs1=100paise$

$Rs34=34\times 100=3400paise$

$50x+25y=\mathrm{3400.....}\left(1\right)$

Given that

$y=2x.............\left(2\right)$

Putting (2) in (1) we get

$50x+25\left(2x\right)=3400$

$50x+50x=3400)$

$100x=3400$

$x=34$

from (2) we get

$y=2x=2\times 34=68$

So,

Number of 50-paise coins$=34$

Number of 25-paise coins$=68$