A man has some hens and cows. If the number of heads be $48$ and the number of feet equals $140$ , then the number of hens will be?

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Solution

$\begin{matrix} N u m b e r o f c o w s = x N u m b e r o f h e n s = y x + y = 48 4 x + 2 y = 140 \Rightarrow 2 x + y = 70 [\begin{matrix} x = 22 - c o w s 4 = 26 - h e n s \end{matrix}] \end{matrix}$

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A man has some hens and cows. If the number of heads be 48 and the number of feet equals 140, then the number of hens will be?

Numberofcows=xNumberofhens=yx+y=484x+2y=140⇒2x+y=70[x=22−cows4=26−hens]

A man has some hens and cows. If the number of heads be $48$ and the number of feet equals $140$ , then the number of hens will be?

$\begin{matrix} N u m b e r o f c o w s = x N u m b e r o f h e n s = y x + y = 48 4 x + 2 y = 140 \Rightarrow 2 x + y = 70 [\begin{matrix} x = 22 - c o w s 4 = 26 - h e n s \end{matrix}] \end{matrix}$