A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of the son is :
22 years
Let the son's present age be x years. then, man's present age = ( x+24) years
∴(x+24) + 2 = 2(x+2)⇔ x = 26=2x+4 ⇔ x = 22.