A man is standing on a weighing machine placed in a lift. When stationary his weight is recorded as 40 kg. If the lift is accelerated upwards with an acceleration of 2m/s2, then the weight recorded in the machine will be (g=10m/s)2
A
32 kg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
40 kg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
42 kg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
48 kg
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D 48 kg When man is stationary
his FBD ⇒N=mg ⇒m=Ng=40kg
When lift accelerates, Pseudo force acts as lift is non-inertial frame.
FBD in non-inertial frame
⇒N′=m(g+a) N′=40(g+a)
Mass reading N′g=40(g+a)g=40(1210)=48kg