The correct option is B 300 m
Let the initial velocity be u. We know the man loses 20% of his velocity after running 108 m.
Hence, velocity at this moment=80% of u=0.8u
∴ Final velocity v=0.8u
Also s=108 m
Using v2=u2+2as,
We get,
⇒(0.8u)2=u2+2a×(108)
⇒216a=0.64u2−u2=−0.36u2
⇒a=−0.36216u2=−1600u2
Now let's assume that the man ran a total distance of x m.
We know,
initial velocity =u
final velocity v=0
Distance covered s=x
Acceleration a=−1600u2
Using v2=u2+2as
We get,
0=(u)2+2ax
→0=u2+2(−1600u2)x
→(1300u2)x=u2
⇒x=300 m
Hence total distance that the man can cover =300 m