Question

A man made a trip of $480km$ in $9$ hours. Some part of the trip was covered with the speed of $45km/hr$ and the remaining at $60km/hr$ . Find the part of the trip covered by him in $60km/hr$.

Answer 1

Total distance of trip $=480$km

Total time of journey $=9$ hrs

Let 'x' hrs be travel with $45$ km/h and rest with $60$ km/h

$15x+60(9-x)=480$

$45x+450-60x=480$

$15x=60$

$[x=4]$

Now, Total distance covered with $60$ km/hr $=60\times 5=300km$.