A man measures the period of a simple pendulum inside a stationary lift and finds it to be T sec. If the lift accelerates upwards with an acceleration g/4, then the period of the pendulum will be
In stationary lifr T = 2π√lg
In upward moving lift T' = 2π√l(g+a)
( a = Acceleration of lift )
⇒T′T=√gg+a=√g(g+g4)=√45⇒T′=2T√5