wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A man of mass 50 kg stands on a frame of mass 30 kg. He pulls on a light rope which passes over a pulley. The other end of the rope is attached to the frame. For the system to be in equilibrium, what force must the man exert on the rope? (Take g=10 m/s2)


A
400 N
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
374 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
418 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
448 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 400 N
Force exerted by man on rope transfers to it in the form of tension.


Net upwards force on the system is 2F.
Net downward force is (50+30)g=80g.
For equilibrium of system, 2F=80g
or F=40g=400 N

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon