wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A man of mass 60kg and a boy of mass 30kg are standing together on frictionless ice surface. If they push each other apart man moves away with a speed of 0.4m/s relative to ice. After 5sec they will be away from each other at a distance of.

A
9.0m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3.0m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
6.0m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
30,
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 6.0m
The man and the boy move in opposite directions.
Momentum of man= momentum of boy
60×0.4=30×v
or velocity of the boy v=0.8ms1
Relative velocity =0.4+0.8=1.2ms1
Distance between them in 5sec =1.2×5=6.0m.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relative Motion
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon